Instruction

1

Find the square to the 1st side. Let's build the number 15 in the square, get the 225.

2

Find square 2nd side. Let's build the number 9 in the square, get 81.

3

Add the results of the 1st and 2nd step. Add 225 to 81, get 306.

4

Calculate the square root of the result of the 3rd step. Root of the number 306 is approximately equal to 17.49 inches. This is the length of the hypotenuse.

Note

If an unknown variable is one of the shorter sides, then at the 3rd step are different. From the square of the hypotenuse subtract the square of the leg. The rest is not changing. For example, was known to the hypotenuse is 17.49 inches. Also known side is 9 cm. Find the length of the other leg.

The number of 17.49 squared is equal to 305.9. The number 9 squared is 81. Subtract from the number to 305.9 81 received 224,9. Calculated from this number the root is received 14.99 inches - the length of the second leg. It turned out a little less than 15 centimeters because of 17.49 - we initially have a rough, rounded value.

The number of 17.49 squared is equal to 305.9. The number 9 squared is 81. Subtract from the number to 305.9 81 received 224,9. Calculated from this number the root is received 14.99 inches - the length of the second leg. It turned out a little less than 15 centimeters because of 17.49 - we initially have a rough, rounded value.

Useful advice

To confidently solve problems by using the Pythagorean theorem, work out a few times. Decide on 50 different tasks with different rectangular triangles. You won't forget this theorem ever.

# Advice 2 : How to find the side of a triangle

Side

**of the triangle**is a direct, limited its vertices. All of them have figures of three, this number determines the number of almost all graphics characteristics: angle, midpoint, bisectors, etc. to find the**side****of the triangle**, you should carefully examine the initial conditions of the problem and determine which of them may be basic or intermediate values to calculate.Instruction

1

The sides

**of the triangle**, like other polygons have their own names: the sides, base, and hypotenuse and legs of the figure with a right angle. This facilitates the calculations and formulas, making them more obvious even if the triangle is arbitrary. The figure of graphics, so it is always possible to arrange so as to make the solution of the problem more visible.2

Sides of any

**triangle**are connected and the other characteristics of the various ratios that help calculate the required value in one or more actions. Thus the more complex the task, the longer the sequence of steps.3

The solution is simplified if the triangle is standard: the words "rectangular", "isosceles", "equilateral" immediately allocate a certain relationship between its sides and angles.

4

The lengths of the sides in a right triangle are connected by Pythagorean theorem: the sum of the squares of the legs equals the square of the hypotenuse. And the angles, in turn, are associated with the parties to the theorem of sines. It affirms the equality relations between the lengths of the sides and the trigonometric function sine of the opposite angle. However, this is true for any

**triangle**.5

Two sides of an isosceles

**triangle**are equal. If their length is known, it is enough only one value to find the third. For example, suppose we know the height held to it. This cut divides the third**side**into two equal parts, and allocates two rectangular**triangle**H. Considered one of them, by the Pythagorean theorem find the leg and multiply it by 2. This will be the length of an unknown side.6

Side

**of the triangle**can be found through other sides, corners, length, altitude, median, bisector, perimeter size, area, inradius, etc. If you can't apply the same formula to produce a series of intermediate calculations.7

Consider an example: find

**side of**an arbitrary**triangle**, knowing the median ma=5, held for her, and the lengths of the other two medians mb=7 and mc=8.8

Resented involves the use of formulas for the median. You need to find the

**way**. Obviously, there should be three equations with three unknowns.9

Write down the formulae for the medians:ma = 1/2•√(2•(b2 + c2) – a2) = 5;mb = 1/2•√(2•(a2 + c2) – b2) = 7;mc = 1/2•√(2•(a2 + b2) – c2) = 8.

10

Express c2 from the third equation and substitute it into the second:c2 = 256 – 2•a2 – 2•b2 b2 = 20 → c2 = 216 – a2.

11

Lift both sides of the first equation in the square and find a by entering explicit values:25 = 1/4•(2•20 + 2•(216 – a2) – a2) → a ≈ 11,1.