You will need

- - ammeter;
- - ohmmeter;
- - wattmeter;
- calculator;
- - technical documentation.

Instruction

1

To convert amps to

**volts**, check the wattage of the appliance or conductor resistance. Power devices can be found in the technical documentation or on the housing. If the documents are not available on the device, check the technical parameters (capacity) on the Internet or measure it with a wattmeter. To determine the resistance of a conductor, use an ohmmeter.2

If you know the power of the appliance, in order to convert amperes to

**volts**, use the following formula:U = P/I where:U – voltage in volts,P is power in watts,I is current in amperes.Under "capacity" means the consumption of electrical power.3

Example.It is known that the electric motor provides the power 1900 watts. Its efficiency is 50%. Thus, the detected engine fuse for 10 amps.Question.What voltage the motor is designed?Solution.To calculate consumption electrical power divide his effective power efficiency:1900 / 0,5 = 3800 (watts).To calculate the voltage, divide the capacity by current:3800 / 10 = 380 V (volts).Response.For the operation of the motor necessary voltage of 380 volts.

4

If you know the electrical resistance of a conductor or a simple heating appliance (e.g. iron), then to convert amps to

**volts**, use Ohm's law: U = IR, where R is the conductor resistance, in ohms5

Example.The resistance of the spiral electric is 110 ohms. Through the plate passes a current of 2 amperes.Question.What is the voltage of the power supply?Solution.U = 2 * 110 = 220 V (volts).Response.Power supply is 220 volts.

6

Example.The resistance of the spiral bulbs for flashlight – 90 ohms. In the on state passes through it a current of 0.05 amps.Question.How many standard elements of the power required for operation of the flashlight?Solution.U = is 0.05 * 90 = 4.5 (the volt). The EMF of a single battery is 1.5 volts, therefore, for a lantern you will need 4,5 / 1,5 = 3 such elements.

# Advice 2: How to convert amps to kilowatts

At the fork, sockets, fuses, machines, counters, etc. set the maximum current, expressed in amperesAh. But the point appliances power consumption is expressed in watts or kilowatts. How do you know what the maximum load capacity can be enabled by using one or another accessory?

Instruction

1

To translate the current of power is not possible if another unknown parameter is the voltage. If the latter are known, and in most cases this is so, use the following formula:

P=UI, where P is power (W), U - voltage (V), I is amperage (A).

P=UI, where P is power (W), U - voltage (V), I is amperage (A).

2

If the voltage is variable, use it current, not peak value. It is in most cases indicated. If it is specified amplitude value of voltage, which happens very rarely, turn it to current by dividing by the square root of two (approximately 1.41, which is enough for most practical calculations).

3

The power calculation result obtained in watts. In case you have value in kilowatts, divide it by a thousand.

4

Sometimes the inverse problem: to determine the current in the circuit, knowing the capacity and voltage to select plugs, sockets, machine, meter, etc. In this case, use the inverse formula:

I=P/U.

I=P/U.

5

If the power is expressed in kilowatts, previously ensure that it is in watts, multiply by a thousand. The voltage value is also a valid use.

6

In case, if the voltage is expressed in kilovoltAh to the value in volts by a trivial multiplication by a thousand is not always. Very often it is in this round. Remember, for example, that the common designation of 0.4 kV has two meanings. In Russia, it is 380 V, and in Europe - 400. However, most loads designed to operate in Europe, can operate at slightly reduced voltage and in Russia. The reverse compatibility cannot be guaranteed.

7

No matter which operations you have performed on the transfer current, power, or Vice versa, never overload no cables or any electrical installation. It threatens their overheating, failure and even fire.

# Advice 3: How to translate amps

Amps is a standard system unit of power (SI). Quite large by domestic standards, so multiple units (kiloampere) in practice are rarely used. But in the specifications of electronic equipment (especially in miniature) is common submultiple – mA. Household appliances generally described in this parameter as power (measured in watts). Connect appliances to the mains you have, has a limit for the current. To avoid constant tripping of the fuse, you will need to understand how, in practice, translate amps to other units.

You will need

- tester;
- calculator;
- - technical documentation for appliances.

Instruction

1

If you want to put the amps in other units of measurement of power (a decimal fraction or a multiple), then just multiply the number of amperes by that factor. For example, to convert amperes to milliamperes, multiply number amperes by 1000 and the transfer of amp to kiloampere – multiply by 0.001. Accordingly, the translation ampere megaampere multiply the amperage at 0,000001 and transfer in microamperes – multiply by 1000000. The rest-fraction and multiple units of measure current in everyday life and in solving standard tasks are not used.

2

To estimate the maximum total power of electrical consumers which are able to withstand your power grid, multiply the current (in amperes), which is designed for a fuse on the line voltage (220 volts). The resulting value will be equal to the power capability of simultaneously connected electrical appliance expressed in watts. So (purely practical) amps can be converted to watts.

3

Similarly, we can calculate the maximum capacity of the electrical equipment when it is connected to Autonomous power sources. As a rule, accumulators and batteries specified voltage and maximum current for which designed power source. When you connect a too-powerful consumer, the power source could fail or even ignite.

4

To determine the power consumption will study the technical documentation of electrostrictive or look for information on the appliance. The electrical power specified in watts (W, W), kilowatts (kW, kW), or milliwatts (mW, mW).

5

Example.

Household electrical network is designed for a maximum current of 20 amps.

Question.

Stavatti how many light bulbs you can turn on at the same time?

Solution.

1. Rate the maximum load power mains: 20(A) * 220(V) = 4400 (W).

2. Divide the total allowable power network to power one light bulb: 4400 (W) / 100 (watt) = 44 (units).

Response.

At the same time you can connect a light bulb 44.

Household electrical network is designed for a maximum current of 20 amps.

Question.

Stavatti how many light bulbs you can turn on at the same time?

Solution.

1. Rate the maximum load power mains: 20(A) * 220(V) = 4400 (W).

2. Divide the total allowable power network to power one light bulb: 4400 (W) / 100 (watt) = 44 (units).

Response.

At the same time you can connect a light bulb 44.

# Advice 4: How to calculate amps

Measured in amperes the strength of electric current. Therefore, in order to calculate

**the amps**, you need to find this physical value. The amperage can be measured with a tester. If this is not possible, you can find out the amperage in the circuit or a specific consumer according to Ohm's law.You will need

- tester;
- - documentation for consumers;
- - a current source.

Instruction

1

To find

**amps**that measure current, use a regular tester, adjusted to measure this value. Plug it into the circuit in series with the consumers. The display will show the current value of. If the tester is configured for multiple or decimal fraction of the value, use the rules for their translation. For example, if the device in the chain shows current 120mA, then divide this number by 1000 and get a value of 0.12 A. If the amperage is equal to 2.3 kA, now multiply the value by 1000 and get the 2300 A.2

If you measure the current you have no chance, find its voltage, which is necessary for the work of the consumer and its electrical resistance (Ohm's Law for subcircuit). To do this, the voltage at this part of the chain U divide by the resistance R (I=U/R). For example, if a household network is connected to the iron with a resistance of 160 Ohms, the current in it is equal to the ratio of stress (in the home network it is equal To 220) to the resistance I=220/160=1,375 A.

3

To determine the strength of the current in the circuit is not measuring the voltage at the consumer, find the EMF (electromotive force) source current and its internal resistance. Determine the resistance of the circuit. Find the amperage by dividing the EMF in the amount of the internal resistance of the source r and external resistance R (I=EMF/(R+R)). For example, if the lamp is connected to a battery with EMF 12 V and has a resistance of 20 Ohms, and the internal resistance of the battery is equal to 4 Ohms, the current in the lamp is equal to I=12/(20+4)=0,5 A.

4

On some devices, such as lamps, indicated their power at rated voltage. Determine the nominal current, which flows through this device, the ratio of power P to the rated voltage U (I=P/U). For example, if the specified lamp, 100 W, 220 V, the current flowing through it is equal to I=100/220?0.45 A.

# Advice 5: How many volts are in one ampere

People make mistakes in the interpretation of the characteristics of electric current, which quite often there is confusion in the name of measured values and units of measurement. Knowledge of basic concepts will help to perceive and transmit information about the electrical systems.

To the question about the ratio of volts to amps is no definite answer. The fact is that it is units of different quantities that do not have a direct connection. Current is measured in Amperes and is a key indicator of the current load, the work done by an electric current in the conductor. In other words, current quantifies the density of the flow directed particles passing through a crystal lattice. Volt is unit of voltage, and it is a completely different value. The voltage is numerically expresses the force which is applied against the flow of electrons, and sets it in motion. By and large, voltage is the difference between a positive and a negative potential on the other ends of the conductor. The greater the difference, the higher the magnetic flux that causes the electrons to move to other parts of the circuit, with a positive charge.

To calculate how many volts are in one ampere can only be provided based on the primary characteristics of a conductor in which a current flows and resistance. After all, if the flow of elementary particle encounters no obstacle, it can set in motion the power of even the smallest magnitude. Resistance numerically expresses the degree of obstruction of the conduit to the passage of electric current. This is reflected in the collisions of electrons with ions of the crystal lattice, due to which the latter are heated. Resistance is the third current-voltage characteristic and is expressed in ohms. The mediator will help to determine what voltage will correspond to a particular value of the current.

Answers the question about volts and amps Ohm's law for homogeneous section of circuit for this, which has no electricity, and there are only consumers. This law States that the force of the current in the circuit increases with increasing voltage and decreases with the increase of the total resistance of this circuit. In other words, the higher electromotive force, the greater the flow, it is able to set in motion, but with increasing resistance it is not enough, causing the flux density falls.

Consider Ohm's law on the example of the usual stavatti the bulb. Power is the product of the current intensity on the square of the voltage, so at 220 Volts in the network flows through the lamp filament current is approximately equal to 0.45 ampere. The resistance of the lamp is equal to the private from dividing the square of the voltage on the power that is 484 Ohm. Using Ohm's law, these quantities are easy to check. The amperage should be equal to the result of dividing the voltage to resistance, that is 220/484 that is approximately equal to 0.45 Ω.

To calculate how many volts are in one ampere can only be provided based on the primary characteristics of a conductor in which a current flows and resistance. After all, if the flow of elementary particle encounters no obstacle, it can set in motion the power of even the smallest magnitude. Resistance numerically expresses the degree of obstruction of the conduit to the passage of electric current. This is reflected in the collisions of electrons with ions of the crystal lattice, due to which the latter are heated. Resistance is the third current-voltage characteristic and is expressed in ohms. The mediator will help to determine what voltage will correspond to a particular value of the current.

Answers the question about volts and amps Ohm's law for homogeneous section of circuit for this, which has no electricity, and there are only consumers. This law States that the force of the current in the circuit increases with increasing voltage and decreases with the increase of the total resistance of this circuit. In other words, the higher electromotive force, the greater the flow, it is able to set in motion, but with increasing resistance it is not enough, causing the flux density falls.

Consider Ohm's law on the example of the usual stavatti the bulb. Power is the product of the current intensity on the square of the voltage, so at 220 Volts in the network flows through the lamp filament current is approximately equal to 0.45 ampere. The resistance of the lamp is equal to the private from dividing the square of the voltage on the power that is 484 Ohm. Using Ohm's law, these quantities are easy to check. The amperage should be equal to the result of dividing the voltage to resistance, that is 220/484 that is approximately equal to 0.45 Ω.