# Advice 1: How to find the volume in physics

The volume characterizes numerically a certain region of space with given boundaries. In several branches of mathematics it calculates the shape of the boundaries and size or cross-sectional area and coordinates. When talking about the physical formula for calculating the amount, usually mean calculations for other parameters of body density and weight. Instruction
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Find out the density (ρ) of the material constituting the physical body, the volume of which you want to calculate. Density is one of the two characteristics of the object involved in the calculation formula of the volume. If we are talking about real objects, the calculations used the average density as homogenous physical body in real conditions it is difficult to imagine. It must be unevenly distributed, at least microscopic voids or inclusions of foreign material. Keep in mind when defining this setting and the temperature - the higher it is, the less the density of the material, since heat increases the distance between its molecules.
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The second parameter, which is needed to calculate volume - mass (m) of the body. This value will be determined, as a rule, the results of the interaction of the object with other objects or created their gravitational fields. This files most often have to deal with the mass, expressed through interaction with the Earth's gravity - the weight of the body. Ways to determine this value for relatively small objects simple - they just need to weigh.
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To calculate the volume (V) of the body divide a certain in the second step, the parameter - weight - the parameter obtained in the first step - the density: V=m/ρ.
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In practical calculations, to the calculations it is possible to use, for example, the calculator volume. It is convenient because does not require to look somewhere else the density of the desired material and enter it into a computer in the form there is a dropdown list with a list of the most frequently used in calculations of materials. Clicking the desired line, enter in the "Weight" weight, and in the "calculation Precision" set the number of decimal places that should be present in the calculations. The volume in liters and cubic meters you'll find in placed below the table. There just in case you will be given the radius of the sphere and the side of the cube, which should correspond to this volume of selected substances.

# Advice 2 : How to find the area and volume of a cube

A cube is a rectangular parallelepiped of which all edges are equal. Therefore, the General formula for the volume of the rectangular prism and the formula for its surface area in the case of Cuba easier. The volume of a cube and the area of the surface can be found, knowing the volume of a sphere inscribed in it, or sphere, described around it. You will need
• the length of a side of a cube, the radius of the inscribed and circumscribed ball
Instruction
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The volume of a box is: V = abc, where a, b, c is its dimension. Therefore, the volume of a cube is equal to V = a*a*a = a^3, where a is the side length of the cube.The surface area of a cube is equal to the sum of the areas of all its faces. Only the cube has six faces, so the area of its surface equal to S = 6*(a^2).
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Let the ball inscribed in the cube. Obviously, the diameter of the ball is equal to the side of the cube. Substituting the length of the diameter in the expression for the volume instead of the length of the edges of the cube and using that the diameter is twice the radius, then get V = d*d*d = 2r*2r*2r = 8*(r^3) where d is the diameter of the inscribed circle, and r is the radius of the inscribed circle.The surface area of the cube will then be equal to S = 6*(d^2) = 24*(r^2).
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Let the ball circumscribed around the cube. Then its diameter will coincide with the diagonal of the cube. The diagonal of the cube passes through the center of the cube and connects two opposite points.
Consider first one of the faces of the cube. The edges of this face are the legs of a right triangle in which the face diagonal d is the hypotenuse. Then by the Pythagorean theorem we get: d = sqrt((a^2)+(a^2)) = sqrt(2)*a.
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Then consider the triangle in which the hypotenuse is the diagonal of a cubeand the diagonal edge of d and one edge of cube a to his legs. Similarly, by the Pythagorean theorem we get: D = sqrt((d^2)+(a^2)) = sqrt(2*(a^2)+(a^2)) = a*sqrt(3).
So, derived the formula of diagonal of a cube is equal to D = a*sqrt(3). Hence, a = D/sqrt(3) = 2R/sqrt(3). Therefore, V = 8*(R^3)/(3*sqrt(3)), where R is the radius of the ball is described.The surface area of a cube is equal to S = 6*((D/sqrt(3))^2) = 6*(D^2)/3 = 2*(D^2) = 8*(R^2).

# Advice 3 : How to find the mass of the square

Sometimes web requests are staggering: how to find the mass or volume of a triangle, square or circle. The answer is no. Square, triangle, etc. – flat shapes, the calculation of mass and volume may only have three-dimensional shapes. And under the square could be a cube or a parallelepiped, one of whose sides is a square. Knowing the parameters of these shapes, you can find the volume and mass. Instruction
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To calculate the volume of a cube or cuboid you need to know three values: length, width and height. To calculate the mass required volume and density of the material of the object (m = v*ρ). The density of gases, liquids, rocks, etc. can be found in the relevant tables.
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Example 1. Find the mass of a granite block, whose length is 7 m, width and height 3 m. the Volume of such a parallelepiped will be equal to V = l*d*h, V = 7m*3M*3M = 63 m3. The density of granite is 2.6 t/m3. The mass of the granite block: 2.6 t/m3 * 63 m3 = 163,8 T. a: 163,8 tonnes.
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You need to consider that the sample may not be uniform or may contain impurities. In this case, you will need not only the density of the base material, but the density of impurities.
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Example 2. Find the mass of a cube with sides 6 cm, which consists of 70% pine and 30% spruce. The volume of a cube with a side l = 6 cm is 216 cm3 (V=l*l*l). The volume that is occupied in the specimen pine, can be calculated using a proportion:216 cm3 - 100% X – 70%; X = 151,2 cm3
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The volume that is occupied by spruce: 216 cm3 - cm3 151,2 = 64,8 cm3. Pine density of 0.52 g/cm3, so the mass of pines, contained in the sample of 0.52 g/cm3*cm3 151,2 = 78,624 g ate Density of 0.45 g/cm3, respectively - the mass is equal to 0.45 g/cm3*64,8 cm3 = amounted to 29.16 g. Answer: the total mass of the sample, consisting of spruce and pine 78,624 g + amounted to 29.16 g = 107,784 g
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And even if you need to calculate the mass of a square sheet metal, then you will calculate the mass of the parallelepiped whose length l, width d and height (sheet thickness) h.
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Example 3. Find the mass of copper square sheet, 10 cm by 10 cm, thickness 0,02 see the Density of copper 89,6 g/cm3. The volume of copper sheet: 10 cm*10 cm*0.02 cm = 2 cm3. m(sheet) = 2 cm3*89,6 g/cm3 = 179,2 g Answer: the mass of the sheet - 179,2 g.
Note
In metal, there is the concept of mass of a square. This refers to the mass of calibrated metal rod with a square cross-section. But, regardless of how "this" is, in fact, this rod is still the same box.
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