Instruction

1

In the calculations based on the formula that connects the angle of incidence (α) on a diffraction grating, the length of its wave (λ), the period

**of the grating**(d), the angle of diffraction (φ) and**order***spectrum*(k). In this formula, the product of the period**of the grating**on the difference between the sines of the angles of diffraction and incidence is equal to the product of the order*of the spectrum*at a wavelength of monochromatic light: d*(sin(φ)-sin(α)) = k*λ.2

Express from the in the first step of the formula for

**the order***of the spectrum*. As a result, you should get equality in the left part which will be the desired value, and the right will be a work period,**gratings**at the difference between the sines of the two known angles to the wavelength of light: k = d*(sin(φ)-sin(α))/λ.3

Because the period

**of the grating**, the wavelength and angle of incidence in the resulting formula are constant,**the order***of the spectrum*depends only on the angle of diffraction. In formula it is expressed through the sine and is in the numerator of the formula. This implies that the larger the sine of this angle, the higher**the order***of the spectrum*. The maximum value that can take the sine is equal to one, so just replace in the formula sin(φ) to unity: k = d*(1-sin(α))/λ. This is the final formula for calculating maximum values of the order of the diffraction*spectrum*.4

Substitute numerical values from the problem and calculate a specific value of the desired characteristics of the diffraction

*spectrum*. The baseline can be said that the falling on a diffraction grating the light is made up of several colours with different wavelengths. In this case, use in calculations, the one which has the smaller value. This value is in the numerator of the formula, therefore, the greatest value of the period*of the spectrum*will be obtained at the lowest value of wavelength.