Instruction

1

Say you have the following task. Was leaking some kind of chemical reaction in which a starting material taken as A and B, turned into products, for example, relatively To and G. That is, the reaction took place according to the following scheme: A + B = B + G. If the concentration of substance B is equal to 0.05 mol/l, and the substance G to 0.02 mol/l, was established a kind of chemical equilibrium. You need to determine what the initial concentrations A0 and B0, if the equilibrium constant Kr is equal to the amount of 0.04?

2

To solve this problem take the equilibrium concentration of the substance And the value of "x" and the concentration of a substance In for "y". And also remember that the equilibrium constant Kr is calculated by the following formula: [V][G]/[A][B].

3

In the course of solving we get the following calculation: 0,04 = 0,02 y /x of 0.05. That is, by simple calculation you will get that y = 0.1 x.

4

Now once again look closely at the above chemical equation. From this it follows that one mole of the substances A and B were formed on one pray compounds In G. Based on this, the initial molar concentration of a can be represented as follows:A0 = x + 0,02 A0 = x + y

5

Remember that the value of "y" as you just defined, is equal to one level of 0.1 x. Transforming these equations in the future, you will get: x + 0,02 = 1.1 x. From this it follows that x = 0.2 mol/l, and then the initial concentration [A0] is equal to 0,2 + 0,02 = 0.22 mol/l.

6

What substance B? The initial concentration B0 is much easier. To determine the equilibrium

**concentration**of the substance necessary to allow the equilibrium concentration of the product-substance of G. That is, [B0] = 0,05 + 0,02 = 0,07 mol/l. the Answer will be: [A0] = 0.22 mol/l, [B0] = 0,07 mol/l. the task is solved.