Say you have the following task. Was leaking some kind of chemical reaction in which a starting material taken as A and B, turned into products, for example, relatively To and G. That is, the reaction took place according to the following scheme: A + B = B + G. If the concentration of substance B is equal to 0.05 mol/l, and the substance G to 0.02 mol/l, was established a kind of chemical equilibrium. You need to determine what the initial concentrations A0 and B0, if the equilibrium constant Kr is equal to the amount of 0.04?
To solve this problem take the equilibrium concentration of the substance And the value of "x" and the concentration of a substance In for "y". And also remember that the equilibrium constant Kr is calculated by the following formula: [V][G]/[A][B].
In the course of solving we get the following calculation: 0,04 = 0,02 y /x of 0.05. That is, by simple calculation you will get that y = 0.1 x.
Now once again look closely at the above chemical equation. From this it follows that one mole of the substances A and B were formed on one pray compounds In G. Based on this, the initial molar concentration of a can be represented as follows:A0 = x + 0,02 A0 = x + y
Remember that the value of "y" as you just defined, is equal to one level of 0.1 x. Transforming these equations in the future, you will get: x + 0,02 = 1.1 x. From this it follows that x = 0.2 mol/l, and then the initial concentration [A0] is equal to 0,2 + 0,02 = 0.22 mol/l.
What substance B? The initial concentration B0 is much easier. To determine the equilibrium concentration of the substance necessary to allow the equilibrium concentration of the product-substance of G. That is, [B0] = 0,05 + 0,02 = 0,07 mol/l. the Answer will be: [A0] = 0.22 mol/l, [B0] = 0,07 mol/l. the task is solved.