You will need

- PC power supply

Instruction

1

In order to increase

**the capacity of****unit***power*, you need to open it.2

Next you need to estimate the size of the transformer. If they make "is 3ґ3ґ3 cell" cm and above, then you can begin to finalize.

3

First, replace the high voltage capacitors. It is advisable to put no less than 470мкфх200В. Chokes are placed only in the low-voltage part

**of the unit***power supply*. They are made in several ways.4

You can try to wind on a ferrite ring wire with varnish insulation. Some people remove the chokes from old blocks

*of power*.5

Smoothing capacitors raspalaut in the empty space in the low-voltage side. Stop and three capacitors 2200мкфх16В.

6

Need to replace the diode Assembly. It is advisable to put 2 or 3 builds MOSPEC S30D40, or something similar. All this is bought in stores.

7

In block

*power*there are channels such as +5V and +12V. Inflated the voltage of the second channel(+12) harmful to your computer. To reduce this figure should be in the yellow breaks actuators to solder quite a powerful diode. The voltage is reduced by 0.6 In that It will protect your computer.8

The result of this work it turns out it is a normal unit

*power*. It will work perfectly for many years. With a powerful new bloc*of power*you will get high performance results.# Advice 2 : How to increase the amperage

According to Ohm's law, increasing the

**current**in the circuit is possible if at least one of two conditions: increase voltage or decrease resistance. In the first case, adjust the source**current**for another with more electromotive force; in the latter, pick up the guides with less resistance.You will need

- the usual tester and tables to determine the specific resistance of substances.

Instruction

1

According to Ohm's law, on the part of the chain the strength

**of the current**depends on two variables. It is directly proportional to the voltage at that location and inversely proportional to its resistance. Total dependence is described by the equation which was derived directly from Ohm's law I=U*S/(ρ*l).2

Assemble the electric circuit which includes a source of

**current**, wire and consumer of electricity. As the source**DC**use a rectifier with adjustable voltage. Connect the circuit to a source after setting it the tester is consistently the consumer that is configured to measure the force**of the current**. Increasing the EMF of the source**current**, take readings of the tester with which it can be concluded that by increasing the voltage on the circuit the strength of**current**in it will increase in proportion.3

The second method of increasing the strength

**of the current**- reducing resistance on the circuit. For this special table to determine the resistivity of the site. To do this, please find out in advance what material is made the conductors. To increase**the power****current**, install conductors with smaller resistivity. The smaller this value, the greater the strength**of the current**in this area.4

If there are no other conductors, change the sizes those are available. Increase the area of their cross section parallel them install the same conductors. If the current flows through one strand of wire parallel install several wires. How many times will increase the sectional area of the wire, so many times will increase the current. If possible, shorten the length of the wire used. How many times will reduce the length of conductors, number of times to increase the strength

**of the current**.5

Ways of increasing the strength of

**the current**can be combined. For example, if you increase the cross-sectional area in 2 times, decrease the length of conductors in 1.5 times, and the EMF of the source**current**to increase to 3 times, will gain increasing force**of the current**you 9 times.# Advice 3 : How to increase the frequency of the current

Due to increased migration along the chain of charges increases the frequency

**of the current**. In turn, the increase in the number migrated per unit of time charges amounted to an increase**of current**in the circuit and reduce its resistance, and this can be achieved by using a circuit with a capacitor.You will need

- - capacitor;
- generator;
- key;
- - wires.

Instruction

1

Assemble the circuit with the capacitor, in which a sinusoidal voltage creates a generator of alternating

**current**.2

At zero voltage in the time circuit key in the first quarter of the period the voltage at the generator terminals will increase, and the capacitor will start charging. In the assembled chain will appear current, but, despite the fact that the voltage on the plates of the generator is still quite small, the value of the

**current**in the circuit will be greatest (the value of its charge).3

Note that decreasing the discharge of the capacitor increased

**current**in the circuit is reduced, and the total discharge current is zero. The value of the voltage on the plates of the capacitor will continue to grow, and at the time of full discharge of the capacitor reaches the maximum value (i.e. the value will be completely opposite to the voltage on the plates of the generator). Thus, we can conclude: in the initial moment of time the current with the greatest power will flock to the uncharged capacitor, and the charging will start to decrease.Note

Remember that an increase in the frequency of the current decreases and the resistance of the capacitor alternating current (capacitive resistance of the capacitor). Thus, the resistance capacity is inversely proportional to the capacitance circuit and the frequency of the feeding current.

Useful advice

Capacitor – a unique item. When he discharged, it behaves like a short circuit – the current through it flows without restrictions, and its value tends to infinity. When he charged, at this point, the circuit is open and the circuit starts to continuously increase. It turns out an interesting relationship – there is voltage but no current, and Vice versa. Therefore, to increase the frequency of the current is possible only in case of a weak capacitor, which is in such a condition with a certain interval as many times as necessary. Use this information when creating a circuit.