Instruction
1
Solve tasks on "Proteins" using the following formula: m(min) = a/b*100%, where m(min) is the minimum molecular weight, a is the atomic or molecular weight of the component b – percentage component. The average molecular weight of one acid residue is 120.
2
Calculate the required value for the topic "Nucleic acids", adhering to the rules Chargaff:1.The amount of adenine equals the amount of thymine, and guanine – cytosine;
2.The number of purine bases equals the number of pyrimidine bases, i.e., A+G = T+C. In the chain of the DNA molecule the distance between the nucleotides is equal to 0.34 nm. Relative molecular mass of one nucleotide is equal to 345.
3
Tasks on the theme of "DNA Code" to solve it with the help of a special table of genetic codes. Thanks to it you will learn what acid encodes a particular genetic code.
4
Calculate the desired response for tasks on the theme "Energy exchange" reaction equation. One of the most frequent is: is c6h12o6 + 6О2 → 6СО2 + 6Н2О.
5
Find the solution of problems on genetics based on a special algorithm. First, define which genes are dominant(A, b) and which recessive(a,b). Is called a dominant gene, the symptom of which is shown in homozygous (AA, AA) and heterozygous state(AA, Bb). Is called a recessive gene, the characteristic which occurs only at the meeting of their genes, ie, in a homozygous state. For example, pea plants with yellow seeds crossed with a pea plant with green seeds. Received of pea plants all had yellow seeds. It is obvious that yellow seed is the dominant trait. Write down the solution of this task : A – the gene responsible for yellow seeds and the gene responsible for green seeds.P: AA x aa
G: A, A
F1: Assistaut tasks of this type with several characteristics, then one sign of label A or A, and second B or B.