You will need

- thermometer, scales or measuring cylinders, table of specific heats of substances.

Instruction

1

The temperature

**of the mixture is**homogeneous, zidkostei use the balance to determine the mass of miscible liquids in kilograms. In the case of water (the most common), you can measure its volume in liters using measuring cylinder. The number of liters numerically equal to the mass of water in kilograms. Measure**the temperature**of each fluid in degrees Celsius. One of them will have a higher**temperature**, and the other smaller. The first will give off heat and the other to pick up. At the end of the process, their temperature will be equal.2

Find the product of mass and the warmer liquid at its

**temperature**and add it to the product of mass and the colder liquid at its**temperature**. The result divide by the sum of the masses of the liquids (t=(m1•t1+m2•t2)/(m1+m2)). The result will be the temperature**of the mixture,**homogeneous liquids. In the practice of mixing should minimize the influence of external factors, so blending is better done in the calorimeter.3

The temperature

**of the mixture**of different idcontainer mix, be sure it is practically possible. For example, to mix water and oil can not be - the oil is on the surface of the water. Find the mass and initial temperature of liquids by the method described in the previous paragraph. In the table of specific heats, find these values for liquids that are mixed.4

After this, make the following sequence of mathematical operations:- find the product of the specific heat capacity of the fluid with a higher initial temperature for its mass and

- find the product of specific heat capacity with a lower initial temperature for its mass and

- find the sum of the numbers obtained under paragraphs 1 and 2;

- find the product of the specific heat capacity of the fluid with a higher initial temperature value of that temperature;

- find the product of the specific heat capacity of the fluid with the smaller initial temperature value of that temperature;

- find the sum of numbers obtained in the paragraphs 4 and 5;

- divide the number obtained in paragraph 3 by the number obtained in paragraph 6. t=(C1•m1•t1+C2•m2•t2)/(C1•m1+C2•m2).

**temperature**;- find the product of specific heat capacity with a lower initial temperature for its mass and

**temperature**;- find the sum of the numbers obtained under paragraphs 1 and 2;

- find the product of the specific heat capacity of the fluid with a higher initial temperature value of that temperature;

- find the product of the specific heat capacity of the fluid with the smaller initial temperature value of that temperature;

- find the sum of numbers obtained in the paragraphs 4 and 5;

- divide the number obtained in paragraph 3 by the number obtained in paragraph 6. t=(C1•m1•t1+C2•m2•t2)/(C1•m1+C2•m2).

# Advice 2 : How to find specific heat

The amount of heat required to heat a body depends on its mass, the change of its temperature and the so-called specific heat of a substance, which comprises the body.

Instruction

1

The specific

C = Q/m(T_2-T_1)

Unit of specific heat capacity has the units in the system SI – (j/kg*K).

**heat capacity**of a substance is the quantity of heat required to heat or cool 1 kg of substance by 1 Kelvin. That is, in other words, if for example the specific heat of water is equal to 4.2 kJ/(kg*K) means that in order to heat one kg of water by one degree, you must pass this kg of water is 4.2 kJ of energy. Specific heat of a substance is given by:C = Q/m(T_2-T_1)

Unit of specific heat capacity has the units in the system SI – (j/kg*K).

2

The specific heat of a body is determined experimentally by using a calorimeter and thermometer. A simple calorimeter consists of a polished metal Cup, then put inside the other metal of glass tubes (for heat insulation) and filled with water or other liquid with known specific

**heat capacity**. Body (solid or liquid), heated to a certain temperature t, is immersed in a calorimeter where temperature is measured. Let the test lowering of the body temperature of the liquid in the calorimeter was equal to t_1, and after the temperature of the water (liquid) and lowered into it the body will be equal, it will be equal ?.3

From the law of conservation of energy it follows that the heat Q given to the heated body, equal to the amount of heat Q_1 obtained with water, and Q_2 obtained by the calorimeter:

Q=Q_1+Q_2

Q=cm(t- ?), Q_1=c_1 m_1 (?-t_1), Q_2=c_2 m_2(?-t_1)

cm(t- ?)= c_1 m_1 (?-t_1)+ c_2 m_2(?-t_1)

here m_1 and c_1 - specific heat and mass of water in the calorimeter, and c_2 m_2 - specific heat and mass of the material of the calorimeter.

This equation expresses the balance of thermal energy, is called the equation of thermal balance. He will find

c=(Q_1+Q_2)/m(t- ?) =( c_1 m_1 (?-t_1)+ c_2 m_2(?-t_1))/m(t- ?) = (c_1 m_1+m_2 c_2)( ?- t_1)/m(t- ?)

Q=Q_1+Q_2

Q=cm(t- ?), Q_1=c_1 m_1 (?-t_1), Q_2=c_2 m_2(?-t_1)

cm(t- ?)= c_1 m_1 (?-t_1)+ c_2 m_2(?-t_1)

here m_1 and c_1 - specific heat and mass of water in the calorimeter, and c_2 m_2 - specific heat and mass of the material of the calorimeter.

This equation expresses the balance of thermal energy, is called the equation of thermal balance. He will find

c=(Q_1+Q_2)/m(t- ?) =( c_1 m_1 (?-t_1)+ c_2 m_2(?-t_1))/m(t- ?) = (c_1 m_1+m_2 c_2)( ?- t_1)/m(t- ?)