You will need
• Explorer;
• - current source;
• - the solenoid;
• - the right gimlet.
Instruction
1
Find the vector of magnetic induction of current-carrying conductor. To do this, connect it to the power source. Flowing a current through a wire by using a tester find its value in amperes. Determine the point where will be measured the magnetic field, from this point drop a perpendicular to the conductor and find its length R. Find the modulus of a vectorand the magnetic induction at a given point. For this purpose, the value of the current I multiply by the magnetic constant μ≈1,26•10^(-6). The result, divide by the length of the perpendicular in meters, and double the number π≈3,14, B=I•μ/(R•2•π). This is the absolute value vectorand the magnetic induction.
2
To find the direction vectorand the magnetic induction, take the right gimlet. Suitable conventional corkscrew. Position it so that the rod was parallel to the conductor. Start to rotate the thumb so that the rod began to move in the same direction as the current. Rotation of the handle will indicate the direction of magnetic field lines.
3
Find the vector magnetic induction loop of wire with a current. To do this, measure the amperage in the coil tester and coil radius with the ruler. To find the module of the magnetic induction inside the coil, the current I multiply by the magnetic constant μ≈1,26•10^(-6). The received result divide by twice the radius R, B=I•μ/(2•R).
4
Determine the direction vectorand the magnetic induction. To do this, the right thumb, install the rod in the center of the loop. Start rotating it in the direction of current in it. Translational movement of the rod will show the direction vectorand the magnetic induction.
5
Calculate the magnetic induction inside the solenoid. To do this, count the number of turns and length, tentatively Express in meters. Connect the solenoid to the source and tester measure the current. Calculate the magnetic field inside the solenoid by multiplying the current I by the number of turns N and the magnetic constant μ≈1,26•10^(-6). The result, divide by the length of the solenoid L, B=N•I•μ/L. the Direction vectorand the magnetic induction inside the solenoid, determine the same as in the case of one turn of the conductor.